Question

Intelligent people can only solve this.The question is tricky,harder than it seems.
find the equation of the straight lines passing through the point (-1,2) and making an angle of 45° with the line x-y+1=0.Also,find the point of intersection of the lines.​

Answer 1

Given

p(-1,2)

m = tan@= tan45 = 1

X - y + 1 = 0

X/(-1) + y/1 = 1

so

p'(-1 ,1)

Now

m=(y1 - y2)/(x1 -x2)

m = infinity

both point is lie on X axis is at 0 so there is no slope of line there for line must be perpendicular to axis.

so equation is

X= -1 and y = 2

A line parallel to X axis is perpendicular at Y so the point of intersection is (2 ,-1)

in attachment pic is attached