Question

Intensity of elecric field that produce force 10^-5N IN charge of 5uc?

Answer 1

$\small{\underline{\sf{\orange{Given:\rightarrow}}}}$

$\sf{Force= 10^{-5}N}$

$\sf{Charge= 5uC}$

$\small{\underline{\sf{\red{Find:\rightarrow}}}}$

Intensity of elecric field

$\small{\underline{\sf{\pink{Formula \ Used:\rightarrow}}}}$

$\boxed{\sf{Electric \ Field = \dfrac{F}{q}}}$

$\huge{\underline{\sf{\blue{Solution :\rightarrow}}}}$

Putting all given values in formula we get,

${\implies E= \dfrac{10^{-5}}{5\times10^{-6}}}$

$\sf{\implies E= \dfrac{10}{5}= 2 N/C }$

$\therefore\:\underline{\textsf{ Intensity \of\ electric\ field \textbf{2N/C}}}.$

$\rule{170}2$

Answer 2

Given ,

Force (f) = 10^(-5) N

Charge (q) = 5 uc or 5 × 10^(-6) c

As we know that ,

The electric field intensity is defined as the force per unit charge

$\boxed{ \sf{Electric \: field \: (E) = \frac{Force}{Charge} }}$

Thus ,

E = {10^(-5)} ÷ {5 × 10^(-6)}

E = 0.2 × 10^(-5 + 6)

E = 0.2 × 10

E = 2 N/c

Therefore ,

• The electric field intensity is 2 N/c