Question

Interest on Rs 12500 at 18% per annum for a period of 2 years and 4 months is ________.

Answer 1

Let "I" be interest on a principal "P" for time "T" at "R %" per annum. Also, let "A'' be the amount.

Then, the formulas, you should know are as follows :

✒️ I = (PRT)/100

✒️ A = P + I

✒️ P = (I×100)/(R×T)

✒️ R = (I × 100)/(P×T)

✒️ T = (I × 100)/(P × R)

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$\bold{\huge{SOLUTION\: :}}$

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GIVEN INFORMATIONS :

(1) P = ₹ 12500

(2) R = 18%

(3) T = 2 years 4 months

=> T = 2 years + (4/12) years

=> T = (28 / 12) years

=> T = 7/3 years.

Interest (I) = ₹ (12500×18×7)/(100×3)}

=> Interest = ₹ 5250 [ANSWER]

Answer 2

$\huge \mathfrak{Hi \: THERE!}$❤

P = ₹ 12500

R = 18%

T = 2 years 4 months

T = 2 years + (4/12) years

T = (28 / 12) years

T = 7/3 years.

Interest (I) = ₹ (12500×18×7)/(100×3)}

Interest = ₹ 5250

$\bold{Thankiess}$☺

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