interior and exterior angle of a regular polygon is 8 ratio 1 find the number of sides of the regular polygon and each exterior angle of the polygon
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let the interior and exterior angles be 8x and 1x respectively
we know, Sun of interior and exterior angle = 360
therefore, 8x + 1x = 360
or 9x= 360
or x= 360/9
or x= 40
therefore
interior angle = 8x = 8×40=320
exterior angle = 1x=1×40=40
since the sum of all exterior angles is 360
therefore we have to divide 360 by 40 to find the no. of sides
360/40= 9
hence this regular polygon have 9 sides.
we know, Sun of interior and exterior angle = 360
therefore, 8x + 1x = 360
or 9x= 360
or x= 360/9
or x= 40
therefore
interior angle = 8x = 8×40=320
exterior angle = 1x=1×40=40
since the sum of all exterior angles is 360
therefore we have to divide 360 by 40 to find the no. of sides
360/40= 9
hence this regular polygon have 9 sides.
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0
Answer:9
Step-by-step explanation:
let the interior and exterior angles be 8x and 1x respectively
we know, Sun of interior and exterior angle = 360
therefore, 8x + 1x = 360
or 9x= 360
or x= 360/9
or x= 40
therefore
interior angle = 8x = 8×40=320
exterior angle = 1x=1×40=40
since the sum of all exterior angles is 360
therefore we have to divide 360 by 40 to find the no. of sides
360/40= 9
hence this regular polygon have 9 sides
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