internal resistance of a cell of emf 2V is 0.1 it is connected to resistance of 0.9. voltage across cell will be
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Answer:
Explanation:
E =2V
r=0.1 ohm
R=3.9 ohm
E=I(r+R)
2=I(0.1+3.9)
2=I×4
I=2/4=0.5A
voltage across cell
V=IR
=0.5×3.9
=1.95V
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