Inteval over which y=1/x^2 decreasing
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Answer:
Correct option is
B
(1,∞)
C
(−∞,−1)
y=x/(1+x2)
y′=(1+x2)2(1+x2)−2x⋅x=(1+x2)21−x2
Since (1+x2)2>0 for all x
Therefore y′<0 for 1−x2<0
⇒ x>1 or x<−1
Therefore, x∈(−∞,−1) or x∈(1,∞).
Thus x/(1+x2) decreases in (−∞,−1] or [1,∞).
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