Question

How many times does 2 occur in ten's and unit's place in the number from 100 to 1000 ? ​

Answer 1

ANSWER:

171

STEP - BY - STEP EXPLANATION:

Step1 -

Let’s suppose XY2 is a 2 digit number with 2 in unit’s place

Number of ways X can be filled = 9 (1–9 numbers excluding 0 as it is a 2 digit number).

Number of ways Y can be filled = 10 (0–9 numbers)

Total number of numbers with 2 in unit’s place = 9*10 = 90

Step2 -

Now, let’s suppose X2Y is a 2 digit number with 2 in ten’s place.

Number of ways X can be filled = 9 (1–9 numbers excluding 0 as it is a 2 digit number).

Number of ways Y can be filled = 9 (0–9 numbers excluding 2 as we are counting this in Step1)

Total number of numbers with 2 in ten’s place = 9*9 = 81

So, number of times 2 occurs in ten’s and unit’s place from 100 to 1000 = 90+81 = 171.

Answer 2

Answer:

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