Question

intigrate with respect to x
{1/cos^2x(sin^2x + cos^2x)}^0 dx
​

Answer 1

We know that

${ \sin(x) }^{2} + { \cos(x) }^{2} = 1$

$\frac{1}{ { \cos(x) }^{2} } = { \sec(x) }^{2}$

and

X^0 = 1

Given

$\int( { \frac{1}{ { \cos(x) }^{2} ( { \sin(x) }^{2} + { \cos(x) }^{2}) } )}^{0} dx$

$\int \: dx \\ x \: + c$

Answer 2

Step-by-step explanation:

{ \sin(x) }^{2} + { \cos(x) }^{2} = 1

\begin{lgathered}\frac{1}{ { \cos(x) }^{2} } = { \sec(x) }^{2} \\\end{lgathered}

and

X^0 = 1

Given

\int( { \frac{1}{ { \cos(x) }^{2} ( { \sin(x) }^{2} + { \cos(x) }^{2}) } )}^{0} dx

\begin{lgathered}\int \: dx \\ x \: + c\end{lgathered}