InTwo angles of polygon are right angles any the remaining are120° each. Find the no of sides in it
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Sum of angles = 2 x 90° + (n - 2) 120°
But Sum = (n-2) 180°
So, (n-2) 180° = 180° + (n-2)120°
(n-2) 60 ° = 180°
n - 2 = 3
n = 5
So, the polygon has 5 sides, so its a pentagon
But Sum = (n-2) 180°
So, (n-2) 180° = 180° + (n-2)120°
(n-2) 60 ° = 180°
n - 2 = 3
n = 5
So, the polygon has 5 sides, so its a pentagon
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We know that the formula for the sum of the interior angles in a polygon is:
(n-2)x180
where n = number of sides
The only way I can think of solving this problem is through trial and error for the polygon is irregular.
The sum of a pentagon's interior angles is 3x180=540º
We know that two of these angles are right angles so
540-(2x90)=360
In order for us to confirm that this is the shape, we must make sure that the remaining degrees are divisible by 120.
360/120 = 3
The 2 right angles and the 3 120º angles give a total of 5 angles with a total sum of 540º.
Since this meets all of the criteria, we can determine that the number of sides in the polygon is 5!
(n-2)x180
where n = number of sides
The only way I can think of solving this problem is through trial and error for the polygon is irregular.
The sum of a pentagon's interior angles is 3x180=540º
We know that two of these angles are right angles so
540-(2x90)=360
In order for us to confirm that this is the shape, we must make sure that the remaining degrees are divisible by 120.
360/120 = 3
The 2 right angles and the 3 120º angles give a total of 5 angles with a total sum of 540º.
Since this meets all of the criteria, we can determine that the number of sides in the polygon is 5!
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