Question

invalidity NC rings r bhai ha en ha
$222 \ti.1215 \sqrt[1]{3}$
​

Answer 1

Given, a

∗

b=a×b+(a×a+b×b)

So.

(i)

we put a=(−3) and b=(−5)

(−3)∗(−5)=(−3)×(−5)+[(−3)×(−3)+(−5)×(−5)]

=15+(9+25)=15+34=49

(ii)

Similarly, a=−6,b=2

(−6)∗2=(−6)×2+[(−6)×(−6)+2×2]

=−12+(36+4)

=−12+40=28

Answer 2

Explanation:

invalidity NC rings r bhai ha en ha

$222 \ti.1215 \sqrt[1]{3}$