Inverse of f (x)=((x^3)+2)/(x-3)
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X should be I think so 7
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f(x) = (x^3)+2/(x-3)
Let f(x) = n
f^-1(n) = x
x = n^3 + 2/n - 3
nx - 3x = n^3 + 2
nx - n^3 = 2 + 3x
n(x - n^2) = 2 + 3x
x - n^2 = 2 + 3x
n^2 = x - 3x - 2
n(n) = - 2x - 2
n = - 2x - 2
f^-1(x) = - 2x - 2
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