Inverse trigonometric functions
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sin^(-¹)[cos{x+x}]
= sin(-¹)[cos2x]
=sin(-¹)[sin√(1-4x²)/1]
= √(1-4x²)
= sin(-¹)[cos2x]
=sin(-¹)[sin√(1-4x²)/1]
= √(1-4x²)
ShivanshTHEMASTERS:
sir galat hai
ans. ana chaiye -π/2
but question me to dia h x ka range π/2toπ
yes
options are - -π/2 , π/2, π, π\2
or jb bhi hm kisi inverse ka value lete o digit me aane chahiye na k radian or thita me
that's what i m getting confused in.
it's a competitive level question
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