Question

Ionization energy of gaseous Na atoms 495.5 kJ mol frequency of light (in s^-1)that ionizes a sodium atom is
A) 7.5 x 10^4 B) 4.76 x 10^14
C) 3.15 x 10^15 D) 1.24 x 10^15

Answer 1

Answer:

D) 1.24×10^15

Explanation:

E=hv

where E= energy

h= Planck's constant

v= frequency

495.5 kJ/mol = 495.5×10^3 J / 6.023×10^23 molecules

v= E/h

= (495.5×10^3/6.023×10^23) J / (6.62×10^23)Js

=12.42×10^14 s^-1

=1.24×10^15 s^-1