ionization energy of He+ is 19.6×10^-18 H atom-1 . The energy of the 1st stationary state(n=1) of Li+2 is:
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E=hcR(1/n1^2–1/n2^2)Z^2
where E is energy, c and R are constant, Z IS ATOMIC NUMBER
So for a particular transition in He(Z=4), Energy is 19.6x10^-18(say A),
the energy for the same transition in lithium(z=3) would be,
A*3^2/2^2=9A/4
so energy for Li+2 transition will be 9*19.6*10^-18/4=44.1*10^-18J per atom
where E is energy, c and R are constant, Z IS ATOMIC NUMBER
So for a particular transition in He(Z=4), Energy is 19.6x10^-18(say A),
the energy for the same transition in lithium(z=3) would be,
A*3^2/2^2=9A/4
so energy for Li+2 transition will be 9*19.6*10^-18/4=44.1*10^-18J per atom
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hope the given attachment is helpful to you
-REGARDS
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