Question

Wch of the following contains maximum number of atoms where a-2.0g hydrogen b-2.0g oxygen c-2.0g nitrogen d-2.0g methane

Answer 1

don't know ............

Answer 2

1 Mole =
$6.023 \times 10power23 \: atoms$
No.of moles(n)=mass/gram molecular weight
N = m/Gmw
mass of the hydrogen=1
Gmw of the hydrogen=2
N = 1/2
mass of oxygen= 16
Gmw if oxygen=32
N= 16/32 =1/2
mass of nitrogen=14
Gmw of nitrogen=28
N =14/28 = 1/2
mass of methane=16
Gmw of methane=16
N= 16/16 = 1
so, here one full mole has mire atoms than half mole.