Question

IP1 and IP2 of Mg are 178 and 348 K. mol^-1. the enthalpy required fro the reaction

Answer 1

HERE IS UR ANSWER

ENTHALPY=IP1+IP2

IP1 MG=178

IP2 MG=348

MOL=^-1

I.E ENTHALPY

IP1+IP2 = 178+348 = 526K.Cal

Answer 2

Answer:

We can calculate the enthalpy of the reaction by adding the IP of the magnesium which are 178Kmol-1 and 348Kmol-1.

So, the value of the ionization potential will result in the enthalpy to be termed as the specific enthalpy which is the total energy of the system along with the pressure and temperature.

So, we get the value of the enthaply to be IP1+IP2 = 178+348 = 526KCal.