Ir both (x-2) and (x-1/2)are factores of px hole square +5x+r prove that p=r plz tell me how to do
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let p(x)=px²+5x+r.Since x-2 ad x-1/2 are factors of p(x). p(2)=0 and p(1/2)=0 p×2²+5×2+r=0 and p(1/2)²+5×1/2+r=0 4p+10+r=0 and p/4+5/2+r=0 4p+r=-10 and p+4r+10=0 4 4p+r=-10 and p+4r+10=0 4p+r=-10 and p+4r=-10 4p+r=p+4r 3p=3r ⇒ p=r Read more on Brainly.in - https://brainly.in/question/41219#readmore
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