iron II sulphide reacts with dilute sulphuric acid to give solutions of iron II sulphate on crystallization,the solutions yields crystal of FeSo4.7H2O.How many grams of these crystal will be obtained if we start with 88 gram of iron 2 sulphide.Please answer fast
Answers
Answered by
13
FeS + H2SO4 = FeSO4 + 7H20 (balance it)
FeSO4 + 7H2O= FeSO4.7H2O
according to the reaction,
87.9 gram of FeS gives = 278 g FeSO4.7H2O
88 gram gives = 278/87.9*88 g FeSO4.7H2O = 278.3 g FeSO4.7H2O
FeSO4 + 7H2O= FeSO4.7H2O
according to the reaction,
87.9 gram of FeS gives = 278 g FeSO4.7H2O
88 gram gives = 278/87.9*88 g FeSO4.7H2O = 278.3 g FeSO4.7H2O
Rudra1231:
answer is 278 gm , kindly write the steps
again write please
first write the reaction b/w Iron II sulphide and dilute sulphuric acid, then balance the equation by adding 7 water of crystallisation and then write the number of FeSO4.7H2O formed
how 278gm ,and 87.8gm is coming , kindly explain
Answered by
2
Explanation:
अमोनिया हाइड्रोक्साइड सॉल्यूशन इज एडिट टू कॉपर सल्फेट सलूशन ऑफ फर्स्ट लिटिल डन इन एक्सिस
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