iron (III) oxide may be obtained from iron (III) sulfide by 'roasting' the ore in oxygen:
4FeS(s) +7O2(g)=2Fe 2O3 (s) + 4 SO2(g)
What mass of Iron (III) oxide can be obtained by the roasting of 744g of the sulphide?
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sryyy I don't know the answer.
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