Iron in the form of fine wire burns in oxygen to form iron (III) oxide.
4Fe(s) + 3O2 (g) → 2Fe2O3 (s)
How many moles of O2 are needed to produce 3.91 mol Fe 2O3?
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Answer:
4Fe+3O2+H2O➡️2Fe2O3+2H2O
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