Question

Is 1.575 g h2c2o4.2h2o in 250 ml solution make it 0.1 N

Answer 1

Answer:

Explanation:

Total mass of oxalic acid is 126

Eqivalent mass is 63

Given mass is 1.575

Given volume is 250

Normality = given mass× 1000

--------------------------

Equi. Mass × given volume

N = 0.1 N

Answer 2

Answer: Yes

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}$

$Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor.  

${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= basicity, for acids  , For $C_2O_4H_2.2H_2O$ , n =2

$C_2H_2O_4.2H_2O\rightarrow C_2O_4.2H_2O++2H^+$

As $C_2H_2O_4.2H_2O$ dissociates to give 2 $H^+$ and thus it has basicity of 2.

${\text{Equivalent weight}}=\frac{126}{2}=63g$

$\text{no of gram equivalents of}C_2H_2O_4.2H_2O=\frac{1.575}{63}=0.025gramequivalents$

$Normality=\frac{0.025\times 1000}{250}=0.1N$

Thus Normality will be 0.1 when 1.575 g  of oxalic acid is dissolved  in 250 ml solution.