Question

is 1/64,1/32,1/8 .........are in g.p

Answer 1

S=21/422/823/1624/32....
S=21/4+2/8+3/16....
S=21/4(1+2/2+3/4+4/8....)
S=21/4(t)
t=1+2/2+3/4+4/8.... (infinite AGP with a=1,r=1/2,d=1)
t=a/(1-r) + dr/(1-r)2
t=2+2=4
S=2

Answer 2

No they are not in AP because by d = 1/64
And
T2 -T1 not equal to T3 - T2