is -150 a term of 11,8,5,2....? with steps give the answer
Answers
Answered by
0
an= -150
d= -3
a=11
an=a+(n-1)d
-150=11+(n-1)-3
-150/-3=11+(n-1)
50-11=n-1
49+1=n
50=n
d= -3
a=11
an=a+(n-1)d
-150=11+(n-1)-3
-150/-3=11+(n-1)
50-11=n-1
49+1=n
50=n
jinse74:
is 150 a term of that sequence
why is the question
Similar questions