Question

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ᴀɴsᴡᴇʀ ᴍʏ ǫᴜᴇsᴛɪᴏɴ....
(ᴍᴀᴛʜs)

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@ ᎦᎯmᎯᎲᖇᎯ......

Answer 1

Width of track = 10 m
Distance between two parallel lines = 60 m
Length of parallel tracks = 106 m
DE = CF = 60 m
Radius of inner semicircle, r = OD = O'C 
                                               = 60/2 m = 30 m
Radius of outer semicircle, R = OA = O'B
                                               = 30 + 10 m = 40 m
Also, AB = CD = EF = GH = 106 m
Distance around the track along its inner edge = CD + EF + 2 × (Circumference of inner semicircle)
= 106 + 106 + (2 × πr) m = 212 + (2 × 22/7 × 30) m
= 2804/7 m
 
Area of the track = Area of ABCD + Area EFGH + 2 × (area of outer semicircle) - 2 × (area of inner semicircle)
 = (AB × CD) + (EF × GH) + 2 × (πr2/2) - 2 × (πR2/2) m2
 = (106 × 10) + (106 × 10) + 2 × π/2 (r2 -R2) m2
 = 4320 m2