Is -150 a term of the AP 11, 8, 5, 2?
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Answered by
4
Tn = - 150
= a + ( n - 1 ) d = - 150
= 11 + ( n - 1 ) × ( - 3 ) = 150
= ( n - 1 ) * -3 = 150 - 11
= n - 1 = 139 / -3
n = - 139 / 3 + 1
N can't be fraction.
Hence, ans. no
= a + ( n - 1 ) d = - 150
= 11 + ( n - 1 ) × ( - 3 ) = 150
= ( n - 1 ) * -3 = 150 - 11
= n - 1 = 139 / -3
n = - 139 / 3 + 1
N can't be fraction.
Hence, ans. no
aks627:
tnx
Answered by
3
no, 150 is not a term of ap 11,8,5,2.
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