is -292 a term of the A. P. 7,4,1,-2,...?
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Answered by
6
Hi ,
7 , 4 , 1 , - 2 ,.... , is an A. p
a = 7 ,
d = a2 - a1
d = 4 - 7 = - 3
Let an = -292
a + ( n - 1 ) d = - 292
7 + ( n - 1 ) ( -3 ) = - 292
( n - 1 ) ( - 3 ) = - 292 - 7
= - 299
n - 1 = ( - 299 ) / ( - 3 )
n = ( 299 / 3 ) + 1
n = ( 299 + 3 ) / 3
n = 302 /3
n is not an integer ,
Therefore ,
- 292 is not a term in given A . P
I hope this helps you.
:)
7 , 4 , 1 , - 2 ,.... , is an A. p
a = 7 ,
d = a2 - a1
d = 4 - 7 = - 3
Let an = -292
a + ( n - 1 ) d = - 292
7 + ( n - 1 ) ( -3 ) = - 292
( n - 1 ) ( - 3 ) = - 292 - 7
= - 299
n - 1 = ( - 299 ) / ( - 3 )
n = ( 299 / 3 ) + 1
n = ( 299 + 3 ) / 3
n = 302 /3
n is not an integer ,
Therefore ,
- 292 is not a term in given A . P
I hope this helps you.
:)
Answered by
2
An= a+(n-1)d
-292=7+(-3n)+3
-292=10-3n
-3n=-302
n=302/3
Since the n terms will come in fraction therefore it is not a term of the A.P
-292=7+(-3n)+3
-292=10-3n
-3n=-302
n=302/3
Since the n terms will come in fraction therefore it is not a term of the A.P
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