Question

Is (2x +1) (3x+2) = 6(x-1) (x-2) a quardatic equation or not?​

Answer 1

Answer:

Thanks for your question...

Your required answer :

• (2x +1) (3x+2) = 6(x-1) (x-2)
• 2x ( 3x + 2 ) + 1 ( 3x + 2 ) = 6x - 6 ( x - 2 )
• 6x² + 4x + 3x + 2 = 6x² - 12x - 6x + 12
• 6x² - 6x² + 7x + 18x + 2 - 12 = 0
• 7x + 18x - 10 = 0

So , it is not Quadratic .

Because quadratic equations have 2 as highest degree or power.

Brainliest Please

Answer 2

Step-by-step explanation:

Solution

$\sf(2x+1)(3x+2)=6(x−1)(x−2) \\ \sf⇒6x^2 +7x+2=6(x^2 −3x+2) \\ \sf⇒6x^2 +7x+2=6x^2 −18x+12 \\ \sf⇒25x=10 \\ \sf⇒x=0.4$

$\sf \red{\therefore \:the \: given \: equation \: is \: not \: a \: quadratic \: equation}$

Quadratic equation

Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power solve for x in the quadratic equation x2 + 4x + 4 = 0.