Question

is 3 x minus 7 Y is equals to 10 and x y is equals to minus 1 find the value of 9 X square + 49 y square​

Answer 1

Answer:

Step-by-step explanation:

we know that

(3x-7y)^2= 9x^2 + 49y^2 - 42xy

(10)^2 + 42(-1) = 9x^2 + 49y^2

9x^2 + 49y^2 = 100-42 = 48

Answer 2

$9x^2 + 49y^2 = 58$

The value is 58

Step-by-step explanation:

We are given the following in the question:

$3x - 7y = 10\\xy = -1$

we have to find the value of

$9x^2 + 49y^2$

We will use the algebraic identity:

$a^2 + b^2 = (a-b)^2 + 2ab$

Putting the values, we get,

$a = 3x\\b = 7y\\(3x)^2 + (7y)^2 = (3x-7y)^2 + 2(3x)(7y)\\9x^2 + 49y^2 = (10)^2 + 42(-1)\\9x^2 + 49y^2 = 100 - 42\\9x^2 + 49y^2 = 58$

Thus, the values is 58.

#LearnMore

If X square + Y square = 49 and x - y = 23 then find the value of x cube - y cube

https://brainly.in/question/14780726