Question

is 3CuS + 8HNO3 -->3CuSO4 + 8NO + 4H2O a redox reaction

Answer 1

Answer:

3 CuS + 8 HNO3 → 3 CuSO4 + 8 NO + 4 H2O

This is an oxidation-reduction (redox) reaction:

3 S-II - 24 e- → 3 SVI

(oxidation)

8 NV + 24 e- → 8 NII

(reduction)

CuS is a reducing agent, HNO3 is an oxidizing agent.