Question

Is 3rd equayion of motion dimensionally correct explain

Answer 1

Answer:

L^2T^-2

Explanation:

Use the equation v^2-u^2=2as

Here 2 is a constant, so we ignore 2 and use the dimensional formulas in the equation

(LT^-1)^2 - (LT^-1)^2 = LT^-2×L

L^2T^-2 - L^2T^-2 = L^2T^-2

L^2T^-2 = L^2T^-2