Question

Is 4392126 divisible by 3 ???​

Answer 1

$\huge\mathbb{Hello!!}$

Step 1 :- Add all the digits of the given number.

$4+3+9+2+1+2+6=27$

Step 2 :- Divide the sum by 3

$27\:is\:divisible\:by\:3.$

Therefore, 4392126 is also divisible by 3.

Answer 2

if we add the digits we will get

4+3+9+2+1+2+6=27

which is clearly divisible by 3.

From the hpothesis that if the sum of the digits of the number is divisible by three ,then the no.will also be divisible by three.

so.the given number is divisible by 3.

hope it helps you dude