Question

Is 6 times the sixth term of an arithmetic progression is equal to the 9 times the 9th term find the 15th term?

Answer 1

Hey there!

Here is your answer:

Points to remember:

>6th term of an AP=a+5d

>similarly 9th term of an AP=a+8d

Where a is the first term and d is the common difference

Given:

6(a+5d)=9(a+8d)

=6a+30d=9a+72d

=6a-9a=72d-30d

= -3a=42d

==>a=42/-3

=-14d

a= -14d//------------(1)

15th term of an AP=

a+14d

=(-14d)+14d

=0

==> The 15 the term of the AP is 0

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Hope it helps!

Thank you

Happy learning ✨