Is 6125 a perfect cube? If not, by which smallest natural number should 6125 be divided so that the quotient is a perfect cube?
Answers
Answered by
2
Answer:
Here is your Answer.
If any query, comment down or mess.age me on inst.agram - sauravsingh0103
Attachments:
Answered by
5
Step-by-step explanation:
Given :-
The Number = 6125
To find :-
Is 6125 a perfect cube? If not, by which smallest natural number should 6125 be divided so that the quotient is a perfect cube?
Solution :-
Given number = 6125
It can be written as
6125 = 5×5×5×7×7
=> 6125 = (5×5×5)×(7×7)
6125 can not be written as the product of three same numbers.
6125 is not a perfect cube.
If we divide 6125 with (7×7) = 49 so that the quotient is a perfect cube
On dividing 6125 by 49
=> 6125/49
It can be written as
=> (5×5×5×7×7)/(7×7)
=> (5×5×5)
=> 125
=> 5³
Therefore, 5³ = 125 , a perfect cube.
Answer :-
1) 6125 is not a perfect cube.
2) 6125 should be divided by 49 so that the quotient is a perfect cube.
Used formulae:-
- A perfect cube is obtained by multiplying the number three times by itself.
- a³ = a×a×a
Attachments:
Similar questions