is (7*5*3*2+3) is a composite number? justify your answer
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after solving the question we get Ans 213 and this number is divisible by 3 so it is a composite no
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(7×5×3×2)+3
=140+3
=143
prime factors of 143 are 1, 11,13, 143
so,it is the product of prime factors of 11×13 and1×143 i.e. it has factors other than one and itself. hence it is a composite number.
you can also write the fundamental theorem of arithmetic i.e. every composite number can be written as the product of primes and this factorisation is unique, apart from the order in which the prime factors occur.
hope it helps you
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