Math, asked by sanjay2551974, 12 days ago

is 93825 divisible by 3, 5 and 9 ? give reason ?​

Answers

Answered by bandarisomasekhar200
0

Answer:

1. with 3 it will get divided.

as,

9+3+8+2+5= 27

27\3 = 9.

2. with 5 it will get divided.

as,

last digit is 5.

3. with 9 it will get divided.

as,

9+3+8+2+5=27

27\9 = 3.

Step-by-step explanation:

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Answered by seelamumareddyp3bjzb
0

Answer:

If Sum of the digits of a given number should be divisible by 3 so the given number will be divisible by 3

9+3+8+2+5=27

27 is exactly divisible by 3

93825 is divisible by 3

The last digit of a given number is 5 or 0

The given number is exactly divisible by 5

93825 is divisible by 5

Sum of the digits of a given number should be divisible by 9

9+3+8+2+5=27

27 is exactly divisible by 9

93825 is divisible by 9

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