Question

is a minus one upon a is equal to 8 and a is not equal to zero find a + 1 upon a​

Answer 1

Answer:

$\frac{1}{a} = 8 \\ a \: not \: equal \: to \: 0$

Step-by-step explanation:

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$\frac{a + 1}{a}$

$\frac{ \frac{1}{8} + 1}{( \frac{1}{8}) } = \frac{ ( \frac{9}{8} )}{( \frac{1}{8}) } = \frac{9 \times 8}{8 \times 1} = \frac{72}{8} = 9$

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