Question

IS....
A voltage v(t) = 141.4 sin(314t + 10') is applied to a circuit and a
steady current flowing through it is given by i(t) = 14.4 sin(314t -
20°). Determine the phase difference between the two.​

Answer 1

Answer:

oho don't know 3574324799

Answer 2

Given info : A voltage v (t) = 141.4 sin (314 t + 10°) is applied to a circuit and the steady current given by i(t) = 14.14 sin (314 t − 20°) is found to flow through it.

Determine :

(i) The p.f. of the circuit.

(ii) The power delivered to the circuit.

(iii) Draw the phasor diagram.

solution : phase difference, Φ = 10° - (-20°) = 30°

so power factor of the circuit = cosΦ = cos30°

= √3/2 = 0.866

The power delivered to the circuit, P = VIcosΦ

here V = 141.4 Volts and I = 14.14 Amp

so, P = 141.4 × 14.14 × cos30°

= 1731.47694 ≈ 1731.5 watt

see diagram shown in figure, this shows phasor diagram.