Question

is alty = 4 is the linear equation in the variable and Whem ze=2 then the value of yºb..ekkknn​

Answer 1

Answer:

Given equations are kx+4y=k−4 and 16x+ky=k

Thus, we have

a

1

=k,b

1

=4,c

1

=−(k−4)

a

2

=16,b

2

=k,c

2

=−k

Here condition is

a

2

a

1

=

b

2

b

1

=

c

2

c

1

⇒

16

k

=

k

4

=

(k)

(k−4)

⇒

16

k

=

k

4

Also

k

4

=

k

k−4

⇒ k

2

=64

⇒ 4k=k

2

−4k

⇒ k=±8

⇒ k

2

−8k=0

⇒ k(k−8)=0

k=0 or k=8 but k=0 is not possible other wise equation will be one variable.

⇒ k=8 is correct value for infinite solution.