Question

Is equal to what
Plz tell me

Answer 1

$8-\left ( \frac{4^{\frac{9}{4}}\sqrt{2*2^2}}{2 \sqrt{2^{-2}}} \right )^{\frac{1}{2}}$

$=8-\left ( \frac{4^{\frac{9}{4}}\sqrt{2*4}}{2 \sqrt{\frac{1}{2^2}}} \right )^{\frac{1}{2}}$

$=8-\left ( \frac{4^{\frac{9}{4}}*2\sqrt{2}}{2 *\frac{1}{2}} \right )^{\frac{1}{2}}$

$=8-\left ( \frac{(2^2)^{\frac{9}{4}}*2\sqrt{2}}{1} \right )^{\frac{1}{2}}$

$=8-\left ( \frac{2^{(2*\frac{9}{4})}*2\sqrt{2}}{1} \right )^{\frac{1}{2}}$

$=8-\left ( 2^{(\frac{9}{2})}*2\sqrt{2} \right )^{\frac{1}{2}}$

$=8-\left ( 2^{(4+\frac{1}{2})}*2\sqrt{2} \right )^{\frac{1}{2}}$

$=8-\left ( 2^4*2^{(\frac{1}{2})}*2\sqrt{2} \right )^{\frac{1}{2}}$

$=8-\left ( 2^4*\sqrt{2}*2\sqrt{2} \right )^{\frac{1}{2}}$

$=8-\left ( 2^4*2\sqrt{2*2} \right )^{\frac{1}{2}}$

$=8-\left ( 2^4*2*2 \right )^{\frac{1}{2}}$

$=8-\left ( 2^6 \right )^{\frac{1}{2}}$

$=8- 2^{(6*\frac{1}{2})}$

$=8- 2^3$

=8-8

=0

Hence 0 is the final answer .