Math, asked by shikhajaiswal, 1 year ago

is equal to X Plus One by X 244

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AddictionBoy: which paper is this
Jaanki: answer is 0?
tnwramit1: is the ans 8?

Answers

Answered by Jaanki
0
Given : 1/x + 1/y = 1/(x+y)
simplify,

(x + y)/xy = 1/(x+y)

(x + y)^2 = xy

x^2 + y^2 + 2xy = xy

or, x^2 + y^2 = -xy  ------(1)

8x^3 - 8y^3 = 8 [ (x-y){ (x^2 + y^2) + xy} ]
                    = 8 [ (x+y){ -xy + xy}]         from (1)
                    = 8 (x-y)(0)
                    = 0  ;)
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