Question

Is it is right that,
Factorise: 6-x-2x^2
We have,
6-x-2x^2
= -2x^2-x+6
= -2(x^2+1/2x-3)
= -2(x^2+1/2x+(1/4)^2-(1/4)^2-3)
= -2((x^2+2×1/4×x+(1/4)^2)-(1/16+3))
= -2((x+1/4)^2_49/16)
= -2((x+1/4)^2-(7/4)^2)
= -2((x+1/4)-7/4)((x+1/4)+7/4)
= -2(x+1/4-7/4)(x+1/4+7/4)
-2(x_3/2)(x+2)
= (-2x+3)(x+2)

Answer 1

$6 - x - 2x {}^{2} = 0 \\ \\ 0 = 2x {}^{2} + x - 6 \\ 0 = 2x^{2} - 4x + 3x - 6 \\ 0 = 2x(x - 2) + 3(x - 2) \\ 0 = (x - 2)(2x + 3) \\ \\ x = 2 \: \: \: \: \: \: \: x = - 3 /2 \\ \\ \\ this \: the \: right \: answer$

this is the right answer