Is it possible for the HCF and LCM of two number to be 18 and 378 respectively ? Justify !! - Guys , Easy solution , please :-)
Answers
Answered by
100
The check is done easily without finding then numbers. Since, LCM is a multiple of HCF, ie., 378 = 21 * 18, the answer is yes.
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Let the numbers be A and B.
product of two numbers = product of LCM and HCF.
A * B = 18 * 378
let A = 18 * M and B = 18 * N
A*B = 18 * 18 * M * N = 18 * 378 = 18 * 18 * 3 * 7 * 1
There are two combinations of numbers for which this is true:
18, 378. and 54 , 126
==============
Let the numbers be A and B.
product of two numbers = product of LCM and HCF.
A * B = 18 * 378
let A = 18 * M and B = 18 * N
A*B = 18 * 18 * M * N = 18 * 378 = 18 * 18 * 3 * 7 * 1
There are two combinations of numbers for which this is true:
18, 378. and 54 , 126
Galaxy:
Thank you sir :-)
Answered by
65
You should know that HCF of two numbers is always a factor of the LCM.
(Why this happens is: HCF is a factor of both the numbers. Both the numbers are factors of LCM. Thus HCF is also a factor of LCM and it is always true.)
Your answer:
Check whether 18 is a factor of 378.
378 ÷ 18 = 21, remainder = 0
Since remainder is 0, 18 is a factor of 378. So It is possible for the HCF and LCM of two number to be 18 and 378 respectively
(Why this happens is: HCF is a factor of both the numbers. Both the numbers are factors of LCM. Thus HCF is also a factor of LCM and it is always true.)
Your answer:
Check whether 18 is a factor of 378.
378 ÷ 18 = 21, remainder = 0
Since remainder is 0, 18 is a factor of 378. So It is possible for the HCF and LCM of two number to be 18 and 378 respectively
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