is it possible log x log y=logxy
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0
Log a + log b = log ab
Log a - log b= log a/b
This is the formula of logarithms
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1
log x log y
=> log (x + y)
But, this is not equal to log xy
I hope this will help you
(-:
=> log (x + y)
But, this is not equal to log xy
I hope this will help you
(-:
abhi569:
Reported answers can't be edited
But.... Still your answer is wrong... I think
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