Is it possible present acceleration in PT graph explain?
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Answer: Yeah it's possible
Explanation: Method 1: Using the position data (distance versus time graph). So, 1/2 a = 1.412 so then a is 2*1.412 =2.824 - thus we have obtained the acceleration from the position graph.
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It was learned earlier in Lesson 4 that the slope of the line on a velocity versus time graph is equal to the acceleration of the object. If the object is moving with an acceleration of +4 m/s/s (i.e., changing its velocity by 4 m/s per second), then the slope of the line will be +4 m/s/s.
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