Is it possible to construct a quadrilateral ABCD in which AB=3 cm, BC=5 cm, ∠B = 120°, ∠C=105°, ∠A=160°
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Answer:
Yes
Step-by-step explanation:
Steps :
Draw AB = 4 cm.
At A, draw ∠PAB = 120°.
At B, draw ∠QBA = 60°.
From BQ, cut BC = 4.5 cm.
From C, draw an arc of radius 5 cm which meets AP at D.
Join CD.
Thus ABCD is the required quadrilateral.
DRAW THE FIGURE BY SEEING THE STEP GIVEN ABOVE
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