Physics, asked by mahay6887, 1 year ago

Is it possible to derive Liouville's Theorem purely from maximum differential entropy?

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Answered by Anonymous
0

Typically in physics (at least the way I learned mechanics), this is derived using the multi-dimensional divergence theorem on the 2N2N-dimensional phase space i.e.  0=∂tρ+∑i=1N(∂(ρqi˙)qi+∂(ρpi˙)pi)0=∂tρ+∑i=1N(∂(ρqi˙)qi+∂(ρpi˙)pi),  and the terms in brackets are simplified using Hamiltonian equation of motion to obtain Liouville's Theorem:  dρdt=∂ρ∂t+∑i(∂ρ∂qiqi˙+∂ρ∂pipi˙)=0dρdt=∂ρ∂t+∑i(∂ρ∂qiqi˙+∂ρ∂pipi˙)=0.  I am wondering if it is possible to derive this without assuming "physics," i.e. Hamiltonian equation of motion, but instead from maximum (differential) entropy principle.  Suppose ρ=ρ(p⃗ ,q⃗ ;t)ρ=ρ(p→,q→;t) is a phase-space distribution with maximum differential entropy H[ρ]=∫−ρlogρdp⃗ dq⃗ H[ρ]=∫−ρlog⁡ρdp→dq→.  Since the entropy is maximized, we can write:  dHdt=ddt∫−ρlogρdp⃗ dq⃗ =∫dp⃗ dq⃗ (−logρ−1)dρdt=0dHdt=ddt∫−ρlog⁡ρdp→dq→=∫dp→dq→(−log⁡ρ−1)dρdt=0 However, does this necessarily imply dρdt=0dρdt=0 ? Or, is there an alternative approach to this problem? One way, perhaps, is to show that the differential entropy H[ρ]=∫−ρlogρdp⃗ dq⃗ H[ρ]=∫−ρlog⁡ρdp→dq→ is (up to a constant) equivalent to Boltzmann's definition of entropy S=kBlog|Γ|S=kBlog⁡|Γ| (again, without assuming physics).

Answered by aman3813
0
Yes this is possible. For derivation see pics...
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