Question

is it possible to design a rectangular park of perimeter 80 m and area 300 m2?

Answer 1

Answer:

Let the length of the rectangle be 'x'&breadth be'y'

p =2(l+b)

2(x+y)=80

x+y =40

y=40-x

A= l×b

x×y=400

x(40-x)=400

40x-x²=400

x²-40x+400=0

-b+/+√b²-4ac/2a

-(-40)+/-√0/2

40/2= 20...

length =20m

breadth=20m

Yes it's possible..