Is It possible to have a regular polygon whose each exterior angle measure 35 justify
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The sum of the exterior angles of a regular polygon is 360 degrees. So if the exterior angles are 32 degrees then the number of sides of the regular polygon will be 360/32 = 11.25. Since a fraction of a side is not possible, there cannot be a regular polygon whose exterior angle is 32 deg. The figure will have to be an irregular polygon with 10 angles of 32 deg and the one last angle as 40 degrees.
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If each exterior angle of a regular polygon is 35°.
And As we know, that the sum of all exterior angles of any regular polygon is 360°.
So, the number of sides in that polygon
= Sum of all angles of a regular polygon / Measure of each angle of the polygon
= 360/ 35°
= 10.28 Sides
THE NUMBER OF SIDES SHOULD BE A NATURAL NUMBER NOT IN FRACTION OR DECIMAL.SO,SUCH A POLYGON IS NOT POSSIBLE.
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