Is it true that product of 3 consentive natural numbers is always divisible by 6 ? justify your answers.
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Give examples of Linear equations whose graph i
(a) parallel to x-axis
(b) parallel to y-axis
(b) parallel to y-axis
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Answered by
2
yes it is true.
example:1×2×3=6
2×3×4=24
3×4×5=60
and as follows
hope,it helps....
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example:1×2×3=6
2×3×4=24
3×4×5=60
and as follows
hope,it helps....
plz mark as brainliest
Answered by
4
That's true.. To prove this:- Ex.:- Let the numbers be n,n+1,n+2
For a number to be divisible by 6, it
must be divisible by 2 and 3 both.
Out of n,n+1,n+2, one number will be
divisible by 2 because if any one of the
numbers is odd the next number will
be even and hence divisible by 2.
Similarly we can say that since the
multiples of 3 repeat after intervals of 3,
one in 3 consecutive numbers will be
divisible by 3.
hope it helps..
please mark it as the brainliest..
For a number to be divisible by 6, it
must be divisible by 2 and 3 both.
Out of n,n+1,n+2, one number will be
divisible by 2 because if any one of the
numbers is odd the next number will
be even and hence divisible by 2.
Similarly we can say that since the
multiples of 3 repeat after intervals of 3,
one in 3 consecutive numbers will be
divisible by 3.
hope it helps..
please mark it as the brainliest..
plz mark it as the brainliest
thank u very much!!
welcome
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