Question

Is log, 1 =0(a > 0,a #1) ? Givereason​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Since we know that

${a}^{0} = 1$

Taking log both the side we get

$log \: {a}^{0} = log \: 1 \\ 0 \times log \: a = log \: 1 \:$

since

$log \: {a}^{b } = b \: log \: a$

hence

$0 = log \: 1$

hence proved